A student throws soft balls out of the window at different angles to the horizontal. All soft balls have the same initial speed `v = 10sqrt3 ms^(-1)`. It turns out that all soft balls landing velocities make angles `30^@` or greater with the horizontal. Find the height h (in m) of the window above the ground.

Explanation

To solve the problem of finding the height \( h \) of the window above the ground, we can follow these steps:

### Step 1: Understand the components of motion
The initial velocity \( v \) of the balls is given as \( 10\sqrt{3} \, \text{m/s} \). When the balls are thrown at an angle \( \theta \) to the horizontal, we can break this velocity into its horizontal and vertical components:
- Horizontal component:
\[ v_x = v \cos(\theta) = 10\sqrt{3} \cos(\theta) \]
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