A small block slides with velocity `v_0=0.5sqrt(gr)` on the horizontal frictiohnless surface as shown in the fig. the block leaves the surface at point C. The angle `theta` in the figure is:

Options

A. `tan^(-1)(3)`
B. `tan^(-1)(6)`
C. `tan^(-1)(sqrt(3)//2)`
D. `tan^(-1)(2//sqrt(3))`

Answer

D

Explanation

Horizontal range `=3 xx 10 sin 60^(@) =15 sqrt3m" "tan alpha =(30)/(15sqrt3)=2//sqrt3= alpha=tan^(-1) (2//sqrt3)`