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A particle describes a horizontal circle in a conical funnel whose inner surface is smooth with speed of `0.5(m)/(s)`. What is the height of the plane of circle from vertex of the funnel?

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The correct Answer is:
A-r, B-q, C-r, D-p

[A-r] [B-q] [C-r] [D-p]
Angle subtended in 1 second `=((arc)/(rad sin ))=(4 xx 1)/(1) =4 rad`
magnitude of displacement `= 2R sin ((2pi-4)/(2))=2sin 2`
`rArr "Distance= speed "xx " time = 4m"`
`|"averange velocity"|=(|"displacements"|)/("time")=2 sin 2`
Angle between initial velocity final velocity vector `=(2pi-4)` final position
`=sqrt2V sqrt(1-cos 4)=sqrt2V sqrt(2 sin^(2) 2)=2V sin 2=8 sin 2`
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