A wheel is subjected to uniform angular acceleration about its axis with its angular velocity is zero . In the first two seconds , it rotates through an angle `theta _(1)` and in the next two seconds , it rotates through an angle `theta _(2)` then the ratio of `theta_(2)//theta_(1)`

Answer

61

Explanation

`theta=omega_(0)t+1/2 alpha t^(2), therefore omega_(0)=0 therefore theta_(0)=1/2 alpha (2)^(2)=2alpha and theta_(2)=1/2 alpha (4)^(2)-theta_(1)`
`rArr theta_(2)=8 alpha -2alpha =6alpha therefore theta_(2)/theta_(1)=(6alpha)/(2alpha)=3`