Home
Class 12
PHYSICS
The escape velocity of a body from the s...

The escape velocity of a body from the surface of the earth is equal to

Text Solution

AI Generated Solution

To find the escape velocity of a body from the surface of the Earth, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Formula for Escape Velocity**: The escape velocity (v) from the surface of a planet is given by the formula: \[ v = \sqrt{2gr} ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GRAVITATION

    VMC MODULES ENGLISH|Exercise LEVEL -0 Short Answer Type – II|13 Videos
  • GRAVITATION

    VMC MODULES ENGLISH|Exercise LEVEL -0 Long Answer Type|3 Videos
  • GRAVITATION

    VMC MODULES ENGLISH|Exercise JEE Advance (Archive) TRUE/FALSE|1 Videos
  • GASEOUS STATE & THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (ARCHIVE )|111 Videos
  • INTRODUCTION TO VECTORS & FORCES

    VMC MODULES ENGLISH|Exercise JEE Advanced ( ARCHIVE LEVEL-2)|12 Videos

Similar Questions

Explore conceptually related problems

The escape velocity of a body from the surface of the earth depends upon (i) the mass of the earth M, (ii) The radius of the eath R, and (iii) the gravitational constnat G. Show that v=ksqrt((GM)/R) , using the dimensional analysis.

Find the escape velocity of a body from the surface of the earth. Given radius of earth = 6.38 xx 10^(6) m .

Knowledge Check

  • The escape velocity from the surface of the earth is (where R_(E) is the radius of the earth )

    A
    `sqrt(2gR_(E))`
    B
    `sqrt(gR_(E))`
    C
    `2sqrt(gR_(E))`
    D
    `sqrt(3gR_(E))`
  • Similar Questions

    Explore conceptually related problems

    Escape velocity of a body from the surface of earth is 11.2km/sec. from the earth surface. If the mass of earth becomes double of its present mass and radius becomes half of its present radius then escape velocity will become

    What is the maximum height attained by a body projected with a velocity equal to one- third of the escape velocity from the surface of the earth? (Radius of the earth=R)

    The escape velocity from the surface of the earth is V_(e) . The escape velcotiy from the surface of a planet whose mass and radius are three times those of the earth, will be

    A particle is given a velocity (v_(e ))/(sqrt(3)) in a vertically upward direction from the surface of the earth, where v_(e ) is the escape velocity from the surface of the earth. Let the radius of the earth be R. The height of the particle above the surface of the earth at the instant it comes to rest is :

    A satelite is revolving in a circular orbit at a height h above the surface of the earth of radius R. The speed of the satellite in its orbit is one-fourth the escape velocity from the surface of the earth. The relation between h and R is

    A body is projected up with a velocity equal to 3//4th of the escape velocity from the surface of the earth. The height it reaches is (Radius of the earth is R )

    Find the temeprature at which the r.m.s. velocity is equal to the escape velocity from the surface of the earth for hydrogen. Escape velocity = 11.2 km//s