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A string of length 2m is fixed at two en...

A string of length 2m is fixed at two ends. It is in resonance with a tuning fork of frequency 240 Hz in its third harmonic. Then speed of wave sound in string and its fundamental frequency is:

A

320m/s, 80Hz

B

180m/s, 120 Hz

C

320 m/s, 120Hz

D

180m/s, 80Hz

Text Solution

Verified by Experts

The correct Answer is:
A
`L = 2.0 m ` `f=240Hz`
`f= (3v)/(2L) = 240 , (3v)/(4) = 240`
`v=320 , f_(0)=(v)/(2L) 80Hz`
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