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A stationary source of sound is emitting sound of frequency `500Hz`. Two observers `A` and `B` lying on the same line as the source, observe frequencies `480Hz` and `530 Hz` respectively. The velocity of `A` and `B` respectively are (in `m//s`), speed of sound `=300m//s`.

A

8,18

B

16,14

C

12,18

D

12,16

Text Solution

Verified by Experts

The correct Answer is:
C

Higher frequency heard will be when observer would move towards the source and lower frequency heard will be when observes moves away from the source.
`therefore 530 = 500 [ (300 + v_(01))/(300 - 0)] rArr v_(01) = 18 m// s`
Also , `480 = 500[(300 - v_(02))/(300 - 0)] rArr V_(02) = 12 m//s`
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