Home
Class 12
PHYSICS
The velocity time relation of a particle...

The velocity time relation of a particle is given by v `= (3t^(2) -2t-1) m//s ` Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .

Text Solution

AI Generated Solution

To solve the problem step by step, we will first determine the time when the velocity of the particle is zero, and then we will calculate the position and acceleration at that time. ### Step 1: Find when the velocity is zero The velocity of the particle is given by the equation: \[ v = 3t^2 - 2t - 1 \] To find when the velocity is zero, we set the equation to zero: \[ 3t^2 - 2t - 1 = 0 \] ...
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise LEVEL 1|75 Videos
  • KINEMATICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise LEVEL 2|65 Videos
  • JEE MAIN REVISON TEST-23

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|1 Videos
  • LAWS OF MOTION

    VMC MODULES ENGLISH|Exercise IMPECCABLE|53 Videos

Similar Questions

Explore conceptually related problems

The velocity of a particle is zero at time t = 2s, then

The velocity of a particle is given by v=(2t^(2)-3t+10)ms^(-1) . Find the instantaneous acceleration at t = 5 s.

The velocity of a particle is given by v=(2t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=2 second.

The velocity of a particle is given by v=(4t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=1 second.

The velocity of a particle is given by v=12+3(t+7t^2) . What is the acceleration of the particle?

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The acceleration of the particle is

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

If the velocity of a particle moving along x-axis is given as v=(3t^(2)-2t) and t=0, x=0 then calculate position of the particle at t=2sec.

The angular velocity of a particle is given by omega=1.5t-3t^(@)+2 , Find the time when its angular acceleration becomes zero.

the angular velocity omega of a particle varies with time t as omega = 5t^2 + 25 rad/s . the angular acceleration of the particle at t=1 s is