Accleration-time graph of a particle mov...

Accleration-time graph of a particle moving in a straight line is as shown in Fig. Velocity of particle at time `t=0` is `2 m//s.` Find the velocity at the end of fourth second.

`6m//s`

` 4 m//s`

` 2 m//s `

` 8m//s `

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The correct Answer is:

Area under a- tgraph =change in velocity ` rArr " "Delta v= v-2(1)/(2) xx 2xx 4 " "rArr " "v= 6ms^(-1) `

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