The displacement x of a particle moving in one dimension under the action of a constant force is related to time t by the equation `t=sqrt(x)+3`, where x is in meter and t is in second. Find the displacement of the particle when its velocity is zero.

Options

A. zero
B. 3 units
C. `sqrt 3 ` units
D. 9 units

Answer

A

Explanation

` x(t) =(t-3)^(2) =t^(2) +9-6t `
` rArr " "v(t) =2t -6 and a (t) =2 " "rArr v(t) =0 ` when t = 3s and x (3) =0