A particle moving in a straight line has velocity-displacement equation as `v = 5 sqrt(1 + s).` Here v is in `ms^-1` and s in metres. Select the correct alternative.

Options

A. Particle is initially at rest.
B. Initial velocity of the particle is 5 m/s and the particle has a constant acceleration of ` 12.5ms ^(-2)`
C. Particle moves with a uniform velocity
D. Acceleration of the particle increase linearly with time

Answer

B

Explanation

` v= 5 sqrt (1+s) rArr v^(2) =25 ( t+s) ` Taking derivative wrts
` 2v (dv)/(ds) =25 rArr a =(VdV)/(ds) =12.5 m//s ^(2) `
`V = 5` When s= 0 ` " "rArr " " `Initial velocity is ` m//s `