A ball is released from the top of a tower. The ratio of work done by force of gravity in 1st second, 2nd second and 3rd second of the motion of ball is

Options

A. `1:2:3`
B. `1 : 4: 16`
C. `1 : 3 : 5`
D. `1 : 9 : 25`

Answer

C

Explanation

`mgs_1 : mgs_2 : mgs_3 = {0 + g/2 [(1) - 1]} : {0 + g/2 (2(2) - 1} : {0 + g/2 [2(3) - 1]} = 1 : 3 : 5 s`.