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Work done when a force F=(hati + 2hat(j...

Work done when a force `F=(hati + 2hat(j) + 3hatk) N` acting on a particle takes it from the point
`r_(1) =(hati + hatk)` the point `r_(2) =(hati -hatj + 2hatk)` is .

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Work done by a force F=(hati+2hatj+3hatk) acting on a particle in displacing it from the point r_(1)=hati+hatj+hatk to the point r_(2)=hati-hatj+hat2k is

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A force (hati-2hatj+3hatk) acts on a particle of position vector (3hati+2hatj+hatk) . Calculate the torque acting on the particle.

A force of (2 hati - 4 hatj + 2 hatk ) N act a point (3 hati+2 hatj -4 hatk) metre form the origin. The magnitude of torque is

The torque of force F =(2hati-3hatj+4hatk) newton acting at the point r=(3hati+2hatj+3hatk) metre about origin is (in N-m)

A uniform force of (3hati+hatj) N acts on a particle of mass 2kg. Hence, the particle is displaced from position (2hati+hatk) m to position (4hati+3hatj-hatk) m. The work done by the force on the particle is

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