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A small block of mass 1kg is released fr...

A small block of mass `1kg` is released from rest at the top of a rough track. The track is circular arc of radius `40m`. The block slides along the track without toppling and a frictional force acts on it in the direction opposite to the instantaneous velocity. The work done in overcoming the friction up to the point Q, as shown in figure. is `150J`. (Take the acceleration due to gravity, `g=10ms^-2`)

The speed of the block when it reaches the point Q is

A

`5 ms^(-1)`

B

`10 ms^(-1)`

C

`10sqrt(3) ms^(-1)`

D

`20 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Using work energy theorem
`mg R sin 30^@ = W_f = 1/2 mv^2 , " "200 - 150 = (v^2)/2 =< v = 10 ms^(-1)` .
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