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The power radiated by a black body is P and it radiates maximum energy at wavelength` lambda_(0)`.If the temperature of the black body is now changed, so that it radiates maximum energy at wavelength `(3)/(4) lambda_(0)`, the power radiated by it becomes nP.The value of n is

A

256/81

B

64/27

C

16/9

D

`4//3`

Text Solution

Verified by Experts

The correct Answer is:
A

From Wien 's Law : `lambda_(m)T="Constant"rArr(T_(2))/(T_(1))=(lamda_(1))/(lamda_(2))=(lamda_(0))/(3lamda_(0)//4)=(4)/(3)`
From Stefan 's law : `(E_(2))/(E_(1))=((T_(2))/(T_(1)))^(4)=(256)/(81)`
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