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A heat source at T = 10^(3) K is connec...

A heat source at T = `10^(3)` K is connected to another heat reservoir at T = `10^(2)` K by a copper slab which is 1 m thick. Given that the thermal conductivity of copper is 0.1 `WK^(-1)m^(-1)`, the energy flux through it in steady state is :

A

`200Wm^(-2)`

B

`120Wm^(-2)`

C

`65Wm^(-2)`

D

`90Wm^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`R=(L)/(KA)=(1)/((0.1)A)=(10)/(A)`
`I=(V)/(R)=(900)/((10)/(A))=90A,(I)/(A)=90`
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