A metal ball of mass 0.1 Kg is heated upto `500^(@)C` and drooped into a vessel of heat capacity `800 JK^(-1)` and containing 0.5 kg wate. The initial temperature of water and vessel is `30^(@)C`. What is the approximate percentage increment in the temperature of the water ? [Specific Heat Capacities of wate and metal are, repectively,`4200 Jkg^(-1) and 400 Jkg^(-1) K^(-1)`

Options

A. `25%`
B. `15%`
C. `30%`
D. `20%`

Answer

D

Explanation

By principle of calorimetry
`0.1xx400(T-500)+0.5xx4200(T-30)+800(T-30)`.
`therefore` Percentage change in temperature of water `20%` .