A thermally insulated vessel contains `150g` of water at `0^(@)C`. Then the air from the vessel is pumped out adiabatically. A fraction of water turms into ice and the rest evaporates at `0^(@)C` itself. The mass of evaporated water will be closest to :
(Latent heat of vaporization of water `=2.10xx10^(6)jkg^(-1)` and Latent heat of Fusion of water `=3.36xx10^(5)jkg^(-1)`)

Options

A. 20 g
B. 150 g
C. 130 g
D. 35 g

Answer

A

Explanation

Let us assume `xx` grams of water vaporizer.
`rArr` amount of water frozen `=(150-X)`
Heat gained by vaporized water = Heat lost by frozen water
`rArrXxxL_(V)=(150-X)xxL_(f)" "Xxx21xx10^(5)=(150-X)xx3.36xx10^(5)`
`rArr21X=504-3.6XrArrx=(504)/(24.36)=20.7g~~20g`