Home
Class 12
MATHS
If the focus and the vertex of a parabol...

If the focus and the vertex of a parabola are (2,3) and (-1,1) respectively, then the directrix is :

A

`3x+2y+14=0`

B

`3x+2y-25=0`

C

`2x-3y+10=0`

D

`2x-3y+14=0`

Text Solution

AI Generated Solution

The correct Answer is:
To find the directrix of the parabola given its focus and vertex, we can follow these steps: ### Step 1: Identify the coordinates of the focus and vertex - Focus (F) = (2, 3) - Vertex (V) = (-1, 1) ### Step 2: Determine the midpoint between the focus and the directrix The vertex of the parabola bisects the line segment joining the focus and the foot of the directrix (D). We can denote the coordinates of the foot of the directrix as (x, y). Using the midpoint formula: \[ V_x = \frac{F_x + D_x}{2} \quad \text{and} \quad V_y = \frac{F_y + D_y}{2} \] Substituting the known values: \[ -1 = \frac{2 + x}{2} \quad \text{and} \quad 1 = \frac{3 + y}{2} \] ### Step 3: Solve for x and y From the first equation: \[ -1 = \frac{2 + x}{2} \implies -2 = 2 + x \implies x = -4 \] From the second equation: \[ 1 = \frac{3 + y}{2} \implies 2 = 3 + y \implies y = -1 \] Thus, the coordinates of the foot of the directrix (D) are (-4, -1). ### Step 4: Find the slope of the axis of the parabola The slope (m) of the axis can be calculated using the coordinates of the focus and vertex: \[ m = \frac{F_y - V_y}{F_x - V_x} = \frac{3 - 1}{2 - (-1)} = \frac{2}{3} \] ### Step 5: Determine the slope of the directrix Since the directrix is perpendicular to the axis, the slope of the directrix (m_d) can be found using the relationship: \[ m \cdot m_d = -1 \implies \frac{2}{3} \cdot m_d = -1 \implies m_d = -\frac{3}{2} \] ### Step 6: Use point-slope form to find the equation of the directrix Using the point-slope form of the line equation: \[ y - y_1 = m(x - x_1) \] Substituting the coordinates of the foot of the directrix (-4, -1) and the slope (-3/2): \[ y - (-1) = -\frac{3}{2}(x - (-4)) \] This simplifies to: \[ y + 1 = -\frac{3}{2}(x + 4) \] \[ y + 1 = -\frac{3}{2}x - 6 \] \[ y = -\frac{3}{2}x - 7 \] ### Step 7: Rearranging to standard form To express this in standard form: \[ \frac{3}{2}x + y + 7 = 0 \implies 3x + 2y + 14 = 0 \] ### Final Answer The equation of the directrix is: \[ 3x + 2y + 14 = 0 \]
Promotional Banner

Topper's Solved these Questions

  • CONIC SECTIONS

    VMC MODULES ENGLISH|Exercise LEVEL - 2|111 Videos
  • CONIC SECTIONS

    VMC MODULES ENGLISH|Exercise Numerical Value Type for JEE Main|15 Videos
  • CONIC SECTIONS

    VMC MODULES ENGLISH|Exercise JEE ADVANCED ARCHIVE|76 Videos
  • COMPLEX NUMBERS

    VMC MODULES ENGLISH|Exercise JEE ARCHIVE|76 Videos
  • DIFFERENTIAL CALCULUS

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|75 Videos

Similar Questions

Explore conceptually related problems

If the vertex and focus of a parabola are (3,3) and (-3,3) respectively, then its equation is

vertex and focus of a parabola are (-1,1) and (2,3) respectively. find the equation of the directrix.

vertex and focus of a parabola are (-1,1) and (2,3) respectively. find the equation of the directrix.

If the focus of a parabola is (0,-3) and its directrix is y=3, then its equation is

If the focus of a parabola is (-2,1) and the directrix has the equation x+y=3 then its vertex is a. (0,3) b. (-1,1/2) c. (-1,2) d. (2,-1)

Find the equation of the parabola whose focus is at (-1, 1) and the directrix is x+y+1=0 .

Find the focus and the equation of the parabola whose vertex is (6, -3) and directrix is 3x-5y+1=0

If the vertex of a parabola is (0,2), directrix on x-axis then its focus is :

Find the equation of the parabola with vertex is at (2,1) and the directrix is x=y-1.

Find the equation of the parabola with focus (-3,0) and the equation of the directrix is x = 3.

VMC MODULES ENGLISH-CONIC SECTIONS-LEVEL - 1
  1. The curve described parametrically by x=t^2+t+1 , and y=t^2-t+1 repres...

    Text Solution

    |

  2. If the focus of a parabola is (-2,1) and the directrix has the equatio...

    Text Solution

    |

  3. If the focus and the vertex of a parabola are (2,3) and (-1,1) respect...

    Text Solution

    |

  4. What is the equation of the parabola, whose vertex and focus are on th...

    Text Solution

    |

  5. The parabola y^2 = kx makes an intercept of length 4 on the line x-2y...

    Text Solution

    |

  6. Find the equation of the parabola whose focus is(1,1) and equation of ...

    Text Solution

    |

  7. The focus of the parabola y^2=x+4y+3, is :

    Text Solution

    |

  8. A variable circle is drawn to touch the line 3x – 4y = 10 and also t...

    Text Solution

    |

  9. Find the coordinates of any point on the parabola whose focus is (0, 1...

    Text Solution

    |

  10. The equation ax^2+4xy+y^2+ax+3y+2=0 represents a parabola. Find the va...

    Text Solution

    |

  11. The point (a ,2a) is an interior point of the region bounded by the pa...

    Text Solution

    |

  12. Consider two points A(at1^2,2at1) and B(at2^2,2at2) lying on the parab...

    Text Solution

    |

  13. Locus of trisection point of any arbitrary double ordinate of the para...

    Text Solution

    |

  14. The equation of the chord of contact of tangents from (2, 5) to the pa...

    Text Solution

    |

  15. The line x-y+2=0 touches the parabola y^2 = 8x at the point (A) (2, -4...

    Text Solution

    |

  16. The locus of the midpoint of the segment joining the focus to a moving...

    Text Solution

    |

  17. If the tangent at (1,7) to curve x^(2)=y-6 touches the circle x^(2)+y...

    Text Solution

    |

  18. Consider two curves C1:y^2=4x ; C2=x^2+y^2-6x+1=0. Then, a. C1 and C2 ...

    Text Solution

    |

  19. At the point of intersection of the curves y^2=4ax" and "xy=c^2, the t...

    Text Solution

    |

  20. If the line px + qy =1m is a tangent to the parabola y^(2) =4ax, then

    Text Solution

    |