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Two straight lines `(y-b)=m_1(x+a)` and `(y-b)=m_2(x+a)` are the tangents of `y^2=4a xdot` Prove `m_1m_2=-1.`

A

`m_1+m_2=0`

B

`m_1m_2=1`

C

`m_1m_2= -1`

D

None of these

Text Solution

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The correct Answer is:
C
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