Home
Class 12
MATHS
The locus of the foot of the perpendicul...

The locus of the foot of the perpendicular from the foci an any tangent to the ellipse `x^(2)/a^(2) + y^(2)/b^(2) = 1`, is

A

`x^2+y^2=a^2+b^2`

B

`x^+y^2=a^2`

C

`cx^2+y^2=b^2`

D

`x^2+y^2=2a^2`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CONIC SECTIONS

    VMC MODULES ENGLISH|Exercise LEVEL - 2|111 Videos

  • CONIC SECTIONS

    VMC MODULES ENGLISH|Exercise Numerical Value Type for JEE Main|15 Videos

  • CONIC SECTIONS

    VMC MODULES ENGLISH|Exercise JEE ADVANCED ARCHIVE|76 Videos

  • COMPLEX NUMBERS

    VMC MODULES ENGLISH|Exercise JEE ARCHIVE|76 Videos

  • DIFFERENTIAL CALCULUS

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|75 Videos

Similar Questions

Explore conceptually related problems

Find the locus of the foot of the perpendicular drawn from the center upon any tangent to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1.

Prove that the product of the perpendicular from the foci on any tangent to the ellips (x^(2))/(a^(2))+(y^(2))/(b^(2)) =1 is equal to b^(2)

If the loucus of the feet of perpendicular from the foci on any tangent to an ellipse (x^(2))/(4) + (y^(2))/(2) =1 is x^(2) + y^(2) =k , then the value of k is _______.

If the locus of the foot of the perpendicular drawn from centre upon any tangent to the ellipse (x^(2))/(40)+(y^(2))/(10)=1 is (x^(2)+y^(2))^(2)=ax^(2)+by^(2) , then (a-b) is equal to

Prove that the product of the perpendiculars from the foci upon any tangent to the ellipse x^2/a^2+y^2/b^2=1 is b^2

Prove that the product of the perpendiculars from the foci upon any tangent to the ellipse x^2/a^2+y^2/b^2=1 is b^2

Show that the locus of the foot of the perpendicular drawn from centre on any tangent to the ellipse b^2x^2+a^2y^2=a^2b^2 is the curve (x^2+y^2)^2=a^2x^2+b^2y^2

Show that the locus of the foot of the perpendicular drawn from focus to a tangent to the hyperbola x^2/a^2 - y^2/b^2 = 1 is x^2 + y^2 = a^2 .

Show that the locus of the foot of the perpendicular drawn from focus to a tangent to the hyperbola x^2/a^2 - y^2/b^2 = 1 is x^2 + y^2 = a^2 .

The sum fo the squares of the perpendicular on any tangent to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 from two points on the mirror axis, each at a distance sqrt(a^(2) - b^(2)) from the centre, is

VMC MODULES ENGLISH-CONIC SECTIONS-LEVEL - 1
  1. The equation of the tangents to the ellipse 4x^(2)+3y^(2)=5, which are...

    Text Solution

    |

  2. The equation of normal to the ellipse 4x^2 +9y^2 = 72 at point (3,2) i...

    Text Solution

    |

  3. The locus of the foot of the perpendicular from the foci an any tangen...

    Text Solution

    |

  4. Show that the tangents drawn at those points of the ellipse (x^(2))/(a...

    Text Solution

    |

  5. Let the two foci of an ellipse be (-1, 0) and (3, 4) and the foot of p...

    Text Solution

    |

  6. Let the two foci of an ellipse be (-1,0) and (3,4) and the foot of per...

    Text Solution

    |

  7. Let the two foci of an ellipse be (-1,0) and (3,4) and the foot of per...

    Text Solution

    |

  8. Find the equation of the normal to the ellipse (x^2)/(a^2)+(y^2)/(b^2)...

    Text Solution

    |

  9. PQ is a double ordinate of the parabola y^(2)=4ax. If the normal at P ...

    Text Solution

    |

  10. The area of the rectangle formed by the perpendicular from the center ...

    Text Solution

    |

  11. The length ofthe normal (terminated by the major axis) at a point of t...

    Text Solution

    |

  12. Find the middle point of the chord intercepted on the line 2x-y+3 =0 b...

    Text Solution

    |

  13. Find the locus of the mid point of chords of the ellipse x^(2)/a^(2)+y...

    Text Solution

    |

  14. CP and CD are conjugate semi-diameters of the ellipse x^(2)/a^(2) + y^...

    Text Solution

    |

  15. The equation of the chord of (x^(2))/(36)+(y^(2))/(9)=1 which is ...

    Text Solution

    |

  16. Ifchord ofcontact ofthe tangents drawn from the point (alpha,beta)to t...

    Text Solution

    |

  17. If P=(x , y),F1=(3,0),F2=(-3,0), and 16 x^2+25 y^2=400 , then P F1+P F...

    Text Solution

    |

  18. If tan alpha tan beta=-(a^(2))/(b^(2), then the chord joining two poin...

    Text Solution

    |

  19. If F1" and "F2 be the feet of perpendicular from the foci S1" and "S2 ...

    Text Solution

    |

  20. The area of the rectangle formed by the perpendicular from the center ...

    Text Solution

    |