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If the straight line xcosalpha+ysinalpha...

If the straight line `xcosalpha+ysinalpha=p` touches the curve `(x^2)/(a^2)-(y^2)/(b^2)=1,` then prove that `a^2cos^2alpha-b^2sin^2alpha=p^2dot`

A

`a^2 cos^2 alpha+b^2 sin^2 alpha = p^2`

B

`a^2 cos^2 alpha-b^2 sin^2 alpha = p^2`

C

`a^2 cos^2 alpha+b^2 cos^2 alpha = p^2`

D

`a^2 sin^2 alpha-b^2 sin^2 alpha = p^2`

Text Solution

Verified by Experts

The correct Answer is:
B
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