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The point of intersection of two tangent...

The point of intersection of two tangents to the hyperbola `(x^2)/(a^2)-(y^2)/(b^2)=1` , the product of whose slopes is `c^2,` lies on the curve: `y^2-b^2=c^2(x^2+a^2)` (B) `y^2+a^2=c^2(x^2-b^2)` (C) `y^2+b^2=c^2(x^2-a^2)` (D) `y^2-a^2=c^2(x^2+b^2)`

A

`y^2-b^2=c^2(x^2+a^2)`

B

`y^2+b^2=c^2(x^2-a^2)`

C

`y^2+a^2=c^2(x^2-b^2)`

D

`y^2-a^2=c^2(x^2+b^2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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