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A normal to the hyperbola (x^2)/4-(y^2)/...

A normal to the hyperbola `(x^2)/4-(y^2)/1=1` has equal intercepts on the positive x- and y-axis. If this normal touches the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1` , then `a^2+b^2` is equal to 5 (b) 25 (c) 16 (d) none of these

A

5

B

16

C

`(25)/(3)`

D

`(16)/(9)`

Text Solution

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The correct Answer is:
C
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