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If the tangents drawn from a point on the hyperbola `x^2-y^2=a^2-b^2` to the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1` make angle `alpha" and "beta` with the transverse axis of the hyperbola then

A

`alpha-beta= pm(pi)/(2)`

B

`alpha+beta= (pi)/(2)`

C

`alpha+beta= pi`

D

`alpha+beta=0`

Text Solution

Verified by Experts

The correct Answer is:
B
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