Home
Class 12
CHEMISTRY
The Delta(r )H^@ (enthalpy of formation)...

The `Delta_(r )H^@` (enthalpy of formation) is positive in :

A

`O_(3)(g)`

B

`NO(g)`

C

`Hl(g)`

D

All of these

Text Solution

AI Generated Solution

The correct Answer is:
To determine in which case the enthalpy of formation (ΔrH°) is positive, we need to analyze each option provided in the question. The enthalpy of formation is defined as the heat change that occurs when one mole of a compound is formed from its constituent elements in their standard states. ### Step-by-Step Solution: 1. **Understanding Enthalpy of Formation**: - Enthalpy of formation (ΔrH°) is positive when energy is required to form a compound from its elements. This typically occurs when the product is less stable than the reactants. 2. **Analyzing Option 1: Ozone (O3)**: - The formation of ozone from oxygen can be represented as: \[ 3 O_2(g) \rightarrow 2 O_3(g) \] - Ozone (O3) is less stable than diatomic oxygen (O2). Therefore, energy is required to convert O2 into O3, indicating that ΔrH° is positive for this reaction. 3. **Analyzing Option 2: Nitric Oxide (NO)**: - The formation of nitric oxide can be represented as: \[ N_2(g) + \frac{1}{2} O_2(g) \rightarrow NO(g) \] - Nitric oxide is a highly reactive species and is less stable than its constituent elements (N2 and O2). Thus, energy is required for this formation, leading to a positive ΔrH°. 4. **Analyzing Option 3: Hydrogen Iodide (HI)**: - The formation of hydrogen iodide can be represented as: \[ \frac{1}{2} H_2(g) + \frac{1}{2} I_2(s) \rightarrow HI(g) \] - Iodine (I2) must be sublimed from its solid state to gaseous state before it can react with hydrogen. This sublimation requires energy, indicating that ΔrH° is also positive for this reaction. 5. **Conclusion**: - Since all three reactions (ozone, nitric oxide, and hydrogen iodide) require energy for their formation, the enthalpy of formation (ΔrH°) is positive in all these cases. Therefore, the correct answer is that ΔrH° is positive for options 1, 2, and 3. ### Final Answer: The enthalpy of formation (ΔrH°) is positive for ozone (O3), nitric oxide (NO), and hydrogen iodide (HI).

To determine in which case the enthalpy of formation (ΔrH°) is positive, we need to analyze each option provided in the question. The enthalpy of formation is defined as the heat change that occurs when one mole of a compound is formed from its constituent elements in their standard states. ### Step-by-Step Solution: 1. **Understanding Enthalpy of Formation**: - Enthalpy of formation (ΔrH°) is positive when energy is required to form a compound from its elements. This typically occurs when the product is less stable than the reactants. 2. **Analyzing Option 1: Ozone (O3)**: ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMOCHEMISTRY

    VMC MODULES ENGLISH|Exercise JEE MAIN (ARCHIVE)|20 Videos
  • THERMOCHEMISTRY

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (ARCHIVE)|31 Videos
  • THERMOCHEMISTRY

    VMC MODULES ENGLISH|Exercise LEVEL-1|75 Videos
  • THEORY OF SOLUTIONS

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|31 Videos
  • THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (ARCHIVE)|44 Videos

Similar Questions

Explore conceptually related problems

Standard enthalpy of formation is zero for

What is standard enthalpy of formation

Knowledge Check

  • For a reaction, C_((s))+O_(2(g))rarrCO_(2(g)) What is the relation between enthalpy of reaction (DeltaH_(r)), enthalpy of formation of CO_(2)(DeltaH_(f)) and enthalpy of combustion of carbon (DeltaH_("comb")) ?

    A
    `DeltaH_(r) gt DeltaH_(f) = DeltaH_("comb")`
    B
    `DeltaH_(r)=DeltaH_(f)=DeltaH_("comb")`
    C
    `DeltaH_(r)=DeltaH_(f)+DeltaH_("comb")`
    D
    `DeltaH_(r)=2xxDeltaH_(f)`
  • Similar Questions

    Explore conceptually related problems

    Standard enthalpy of formation is non zero for

    C_(2)H_(2) + 5/2 O_2(2) rarr 2CO_(2) + H_(2)O , Delta H = -310 kcal C + O_(2) rarr CO_(2) , " "Delta H = -94 kcal H_(2) + 1/2 O_(2) rarr H_(2)O, " " Delta H = -68 kcal On the basis of the above equations, DeltaH_(f) (enthalpy of formation) of C_2H_2 will be :

    Standard molar enthalpy of formation, Delta_(f) H^(Θ) is just a special case of enthalpy of reaction, Delta_(r) H^(Θ) . Is the Delta_(r) H^(Θ) same as standard molar enthalpy of formation ? Given reason for your answer. CaO (s) + CO_(2) (g) rarr CaCO_(3) (s) , Delta_(f) H^(Θ) = - 178.3 kJ mol^(-1)

    The standard enthalpy of formation of octane (C_(8)H_(18)) is -250kJ //mol . Calculate the enthalpy of combustion of C_(8)H_(18) . The enthalpy of formation of CO_(2)(g) and H_(2)O(l) are -394 kJ//mol and -286kJ//mol respectively.

    In Ellingham diagrams plots of Delta_(f)G (oxide formation) show positive slope except for the formation of CO(g) from coke. Why ?

    In Ellingham diagrams plots of Delta_(f)G (oxide formation) show positive slope except for the formation of CO(g) from coke. Why ?

    Assertion (A): The enthalpy of formation of HCI is equal to the bond energy of HCI . Reason (R ) : The enthalpy of formation and the bond enegry both involve formation of one mole of HCI from the elements.