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In the reaction 2H(2)(g) + O(2)(g) rarr...

In the reaction `2H_(2)(g) + O_(2)(g) rarr 2H_(2)O (l), " "Delta H = - xkJ`

A

x kJ is the heat of formation of `H_2O`

B

` x kJ` is the heat of reaction

C

x kJ is the heat of combusion of `H_2`

D

`x/2 kJ` is the heat of formation of `H_2O`

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The correct Answer is:
To solve the question regarding the reaction \( 2H_2(g) + O_2(g) \rightarrow 2H_2O(l) \) with the enthalpy change represented as \( \Delta H = -x \) kJ, we will analyze each option provided in the context of thermochemistry. ### Step-by-Step Solution: 1. **Understanding the Reaction**: - The reaction involves the combustion of hydrogen gas to form water. The enthalpy change \( \Delta H \) is negative, indicating that the reaction is exothermic (releases heat). 2. **Analyzing Option 1**: - The first option states that \( x \) kJ is the heat of formation of \( H_2 \). - **Heat of formation** refers to the heat change when one mole of a compound is formed from its elements in their standard states. Since \( H_2 \) is an element in its standard state, this option is incorrect. 3. **Analyzing Option 2**: - The second option states that \( x \) kJ is the heat of reaction. - Since the reaction releases \( -x \) kJ, this means that \( x \) kJ is indeed the heat of reaction for the formation of water from hydrogen and oxygen. This option is correct. 4. **Analyzing Option 3**: - The third option states that \( x \) kJ is the heat of combustion of \( H_2 \). - The heat of combustion refers to the heat released when one mole of a substance is completely burned in oxygen. In this reaction, 2 moles of \( H_2 \) are combusted, so \( x \) kJ does not represent the heat of combustion of \( H_2 \) alone. This option is incorrect. 5. **Analyzing Option 4**: - The fourth option states that \( \frac{x}{2} \) kJ is the heat of formation of \( H_2 \). - If we rewrite the reaction to form one mole of water, we have: \[ H_2(g) + \frac{1}{2}O_2(g) \rightarrow H_2O(l) \] - The enthalpy change for this reaction would be \( -\frac{x}{2} \) kJ, which corresponds to the heat of formation of one mole of \( H_2O \). This option is correct. ### Conclusion: - The correct answers are: - Option 2: \( x \) kJ is the heat of reaction. - Option 4: \( \frac{x}{2} \) kJ is the heat of formation of \( H_2O \).

To solve the question regarding the reaction \( 2H_2(g) + O_2(g) \rightarrow 2H_2O(l) \) with the enthalpy change represented as \( \Delta H = -x \) kJ, we will analyze each option provided in the context of thermochemistry. ### Step-by-Step Solution: 1. **Understanding the Reaction**: - The reaction involves the combustion of hydrogen gas to form water. The enthalpy change \( \Delta H \) is negative, indicating that the reaction is exothermic (releases heat). 2. **Analyzing Option 1**: ...
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