The internal energy change `(DeltaU)` for the reaction `CH_(4)(g) + 2O_(2)(g) to CO_(2)(g) + 2H_(2)O(l)` is `-885 kJ mol^(-1)` at 298K. What is `DeltaH` at 398 K?

Explanation

To find the enthalpy change (ΔH) at 398 K for the reaction given, we will first calculate ΔH at 298 K using the relationship between internal energy change (ΔU) and enthalpy change (ΔH). Then, we can estimate ΔH at 398 K using the temperature dependence of enthalpy.

### Step-by-Step Solution:

1. **Identify the given values:**
- ΔU = -885 kJ/mol (internal energy change at 298 K)
- T1 = 298 K
- T2 = 398 K
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