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The enthalpy change on freezing of 1 mol...

The enthalpy change on freezing of 1 mol of water at `5^(@)C` to ice at `-5^(@)C` is:
(Given `Delta_("fus") H = 6 kJ "mol"^(-1) "at" 0^(@)C`,
`C_(p) (H_(2) O, l) = 75.3 J "mol"^(-1) K^(-1),`
`C_(p) (H_(2) O, S) = 36.8 J"mol"^(-1) K^(-1))`

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Enthalpy change for the conversion of 1 mole liquid water at `10^(@)` C into 1 mole liquid `DeltaH_(1) = C_(p)H_(2)O(l) xx DeltaT = -75.3 J mol^(-1)K^(-1) xx 10 R = -753 Jmol^(-1)`
Enthalpy of fusion,
`DeltaH_(2) =DeltaH_("freezing") = -DeltaH_("fusion") = -6.303 kJ mol^(-1)`
Enthalpy change for the conversion of 1 mole of ice at `0^(@)` C to 1 mole of ice at `10^(@)` c.
`DeltaH_(3) = C-(p)H_(2)O(s) xx DeltaT = -36.8 J mol^(-1)K^(-1) xx 10 K = -368 Jmol^(-1)`
`DeltaH_("total") = -(0.753 + 6.03 0.368) kJ mol^(-1) = -7.151 kJ mol^(-1)`
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