When `1`-pentyne `(A)` is treated with `4N` alcoholic `KOH` at `175^(@)C`, it is converted slowely into an equilibrium mixture of `1.3% 1`-pentyne `(A), 95.2%2`-pentyne `(B)`,and `3.5%` of `1,2`-pentadiene `(C )`. The equilibrium is maintained at `175^(@)C`. Calculate `DeltaG^(Theta)` for the following equilibria.
`B hArr A, DeltaG_(1)^(Theta) = ?`
`B hArr C, DeltaG_(2)^(Theta) = ?`
From the calculated values of `DeltaG_(1)^(Theta)` and `DeltaG_(2)^(Theta)`, indicate the order of stability of `A, B`, and `C`.

Explanation

`DeltaG_(1)^(@) = 16 kJ, DeltaG_(2)^(@) = 12.3 kJ`