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One mole of a non-ideal gas undergoes a ...

One mole of a non-ideal gas undergoes a change of state `(2.0 atm, 3.0 L, 95 K) rarr (4.0 atm, 5.0L, 245 K)` with a change in internal energy, `DeltaE = 30.0 L-atm`. The change in enthalpy `(DeltaH)` of the process in `L-atm` is

A

40

B

42.3

C

44

D

not defined, because pressure is not constant

Text Solution

Verified by Experts

The correct Answer is:
c
`DeltaH = DeltaU + Delta(pv), DeltaH = DeltaU + (p_(2)V_(2)-p_(1)v_(1))`
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