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For the reaction equilibrium, N2O4 (g...

For the reaction equilibrium,
` N_2O_4 (g) hArr 2NO_2 (g)`
the concentrations of ` N_2O_4 and NO_2 ` at equilibrium are ` 4.8 xx 10^(-2) and 1.2 xx 10 ^(-2) " mol " L^(-1)` respectively . The value of `K_c ` for the reaction is

A

`3 xx 10^(-3) mol//L`

B

`3.3 xx 10^(-3) mol//L`

C

`3 xx 10^(-1) mol//L`

D

`3.3 xx 10^(-1) mol//L`

Text Solution

Verified by Experts

The correct Answer is:
A
`N_(2)O_(4)(g) rarr 2NO_(2)(g) implies k_(c) = [NO_(2)]^(2)/[N_(2)O_(4)]`
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