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0.1 mole of N(2)O(4)(g) was sealed in a ...

0.1 mole of `N_(2)O_(4)(g)` was sealed in a tude under one atmospheric conditions at `25^(@)C` Calculate the number of moles of `NO_(2)(g)` present , if the equilibrium `N_(2)O_(4)(g)hArr2NO_(2)(g)(K_(P)=0.14)` is reached after some time :

A

0.04

B

0.034

C

0.46

D

0.54

Text Solution

Verified by Experts

The correct Answer is:
B
`N_(2)O_(4) rarr 2NO_(2)`
`K_(p) = (2x)^(2)/(0.1 - x) xx [p/(0.1 + x)]`
`K_(p) = 40 xx x^(2)/(0.1-x)`
x = 0.017
`NO_(2) = 0.017 xx 2 = 0.034 mol e`
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