The equilibrium constant `K_(p_(1))` and `K_(p_(2))` for the reactions `XhArr2Y` and `ZhArrP+Q`, respectively are in the ratio of `1:9` .If the degree of the dissociation of X and Z be equal , then the ratio of the total pressure at these equlibria is

Options

A. `1:36`
B. `1:1`
C. `1:3`
D. `1:9`

Answer

A

Explanation

`(K_(P_(1)) = P_(y)^(2)/P_(x))`
`K_(P_(2)) = P_(p)P_(q)/P_(z)`
Let total pressure `P_(1) implies K_(P_(1)) = (2x/1+x)P_(1)^(2)/((1-x/1+x)P_(1))`
Let total pressure `P_(2) implies K_(P_(2)) = (x/1+x)P_(2)(x/1+x)P_(2)/((1-x/1+x)P_(2))`
Given : `K_(P_(1)):K_(P_(2)) = 1:9`
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