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The equilibrium constant K(c) for the re...

The equilibrium constant `K_(c)` for the reaction
`P_(4)(g)hArr 2P_(2)(g)`
is 1.4 at `400^(@)C.`Suppose that 3 moles of `P_(4)(g)` and 2 moles of `P_(2)(g)`are mixed in 2 litre container at`400^(@)C.` What is the value of reaction quotient`(Q_(c))`?

A

`3/2`

B

`2/3`

C

1

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`Q_(c) = [P_(2)(g)]^(2)/[P_(4)(g)] = (1)^(2)/(3//2) = 2/3`
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