The approach to the following equilibrium was observed kinetically form both directions:
`[PtCl_(4)]^(2-) +H_(2)O hArr [Pt(H_(2)O)Cl_(3)]^(ɵ)+Cl^(ɵ)`
At `25^(@)C` it was found that at `0.3` inoic strength `- (Delta [PtCl_(4)]^(2-))/(Delta t) = (3.9 xx 10^(-5)s^(-1))[PtCl_(4)]^(2-)`
`- (2.1 xx 10^(-3) L mol^(-1) s^(-1))[Pt(H_(2)O)Cl_(3)]^(ɵ)[Cl_(3)^(ɵ)]`
What is the value of `k` for the complexation of the fourth `Cl^(ɵ)` by `Pt(II)` at `0.3` ionic strenght.

Explanation

Equilibrium constant `K_(c)` for backward reaction is
`K_(c) = K_(b)/K_(f) = 2.1 xx 10^(-3)/(3.9 xx 10^(-5)) = 53.85 litremol^(-1)`