Home
Class 12
CHEMISTRY
The degree of ionisation of a 0.1 M br...

The degree of ionisation of a 0.1 M bromoacetic acid solution is 0.132. Calculate the pH of the solution and the `rhoK_a` bromoacetic acid.

Text Solution

Verified by Experts

`CH_(2)(Br)COOH + H_(2)O to CH_(2)(Br)COO^(-) + H_(3)O^(+)`
Initial conc. C 0 0
Equil. Conc. `C-Calpha` `Calpha` `Calpha`
`K_(a)=(Calpha.Calpha)/(C(1-alpha))=(Calpha^(2))/(1-alpha)implies K_(a)=Calpha^(2)` [For weak acid `(1-alpha)approx1`]
`K_(a)=0.1xx(0.132)^(2)=0.00174 approx 1.74xx10^(-3)`
`pH=-logsqrt(K_(a)C)=-logsqrt(1.74xx10^(-3)xx0.1)=1.88` `[H^(+)]=Calpha=sqrt(K_(a)xxC)]`
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise LEVEL 1|75 Videos
  • IONIC EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise LEVEL 2|50 Videos
  • INTRODUCTION TO ORGANIC CHEMISTRY

    VMC MODULES ENGLISH|Exercise JEE ADVANCED ARCHIVE|81 Videos
  • JEE MAIN - 5

    VMC MODULES ENGLISH|Exercise PART II : CHEMISTRY (SECTION - 2)|5 Videos

Similar Questions

Explore conceptually related problems

Calculate the pH of a 0.01 M of HCl solution.

Calculate the pH of 0.05M sodium acetate solution, if the pK_(a) of acetic acid is 4.74 .

Calculate the pH of a 0.01 M of NaOH solution.

Calculate the pH of 1.0xx10^(3) M solution of NaCI

The degree of dissociation of acetic acid in a 0.1 M solution is 1.32xx10^(-2) , find out the pKa :-

The degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionisation constant would be :

The degree of dissociation of acetic acid in a 0.1 M solution is 1.0xx10^(-2) . The pK_(a) of acetic acid value.

The pH of a 0.002 N acetic acid solution , if it is 2.3% ionised at a given dilution ?

The ionization constant of acetic acid 1.74xx10^(-5) . Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH .

The pH of 0.05 M solution of a strong dibasic acid is