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What is the pH of 0.001 M aniline soluti...

What is the `pH` of `0.001 M` aniline solution? The ionization constant of aniline `4.27xx10^(-10)`. Calculate the degree of ionization of aniline in the solution. Also calculate the ionization constant of the conjugate acid of aniline.

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`C_(6)H_(5)NH_(2) + H_(2)O to C_(6)H_(5)NH_(3)^(+) + OH^(-)`
`K_(b)=([C_(6)H_(5)NH_(3)^(+)][OH^(-)])/([C_(6)H_(5)NH_(2)])`=`([OH^(-)]^(2))/([C_(6)H_(5)NH_(2)])`
`[OH^(-)]=sqrt(K_(b).C]=sqrt(4.27xx10^(-10)xx0.001)=6.534xx10^(-7)`
`pOH=-log[6.534xx10^(-7)]=7+(-0.8152)=6.18`
For Base and Conjugate acid pair we have : pH + pOH=14
or pH of conjugate acid =14-6.18=7.82
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