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CH(3)COOH is weaker acid than H(2)SO(4)....

`CH_(3)COOH` is weaker acid than `H_(2)SO_(4)`. It is due to

A

More ionisation

B

Less ionisation

C

Covalent bond

D

Electrovalent bond

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AI Generated Solution

The correct Answer is:
To determine why CH₃COOH (acetic acid) is a weaker acid than H₂SO₄ (sulfuric acid), we can analyze the properties of both acids in terms of their ionization in water. ### Step-by-Step Solution: 1. **Definition of Weak and Strong Acids**: - A weak acid is one that partially dissociates into ions in an aqueous solution. In contrast, a strong acid completely dissociates into ions when dissolved in water. 2. **Ionization of Acetic Acid (CH₃COOH)**: - When acetic acid is dissolved in water, it ionizes as follows: \[ \text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}^+ \] - This reaction shows that acetic acid produces one hydrogen ion (H⁺) and one acetate ion (CH₃COO⁻). This indicates that acetic acid has a limited degree of ionization. 3. **Ionization of Sulfuric Acid (H₂SO₄)**: - Sulfuric acid, on the other hand, ionizes in two steps: \[ \text{H}_2\text{SO}_4 \rightarrow \text{H}^+ + \text{HSO}_4^- \] \[ \text{HSO}_4^- \rightleftharpoons \text{H}^+ + \text{SO}_4^{2-} \] - In the first step, sulfuric acid produces one hydrogen ion (H⁺) and one hydrogen sulfate ion (HSO₄⁻). In the second step, the hydrogen sulfate ion can further dissociate to produce another hydrogen ion (H⁺) and a sulfate ion (SO₄²⁻). Thus, sulfuric acid can produce a total of two hydrogen ions. 4. **Comparison of Ionization**: - Since H₂SO₄ can produce more hydrogen ions (two) compared to CH₃COOH (one), it indicates that H₂SO₄ has a higher degree of ionization than CH₃COOH. - The greater the number of hydrogen ions produced, the stronger the acid. Therefore, H₂SO₄ is a strong acid, while CH₃COOH is a weak acid. 5. **Conclusion**: - The reason CH₃COOH is a weaker acid than H₂SO₄ is due to its **less ionization** in water compared to sulfuric acid. ### Final Answer: CH₃COOH is a weaker acid than H₂SO₄ due to **less ionization**. ---

To determine why CH₃COOH (acetic acid) is a weaker acid than H₂SO₄ (sulfuric acid), we can analyze the properties of both acids in terms of their ionization in water. ### Step-by-Step Solution: 1. **Definition of Weak and Strong Acids**: - A weak acid is one that partially dissociates into ions in an aqueous solution. In contrast, a strong acid completely dissociates into ions when dissolved in water. 2. **Ionization of Acetic Acid (CH₃COOH)**: ...
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Hydrolysis is an acid-basedreaction of a cation or anion or both ions of a salt with water, Resultan solution of hydrolysis may be acidic, basic or netural. The anion A^(-) which is a weakeer base than OH^(-) and which his its conjugate acid HA stronger then water but weaker than H_(3)O shown the phenomenon of hydrolysis Ex : CH_(3)COO^(-),CN^(-),NO_(2)^(-) etc. The contion B^(+) which is a weaker acid than H_(3)^(+) which is a weaker acid then H_(3)^(+) and which has its conjugate base BOH stronger than water but weak than OH^(-) shown the phenmenon of hydrolysis Ex : NH_(4)^(+)C_(6)H_(5)NH^(+),N_(2)H_(5)^(+) etc. The hydrolysis constant of anion and cation are given by A^(-)(aq.)+H_(2)O(l)hArrHA(aq.)+OH^(-)(aq) " " K_(h)=(K_(w))/(K_(a))rArr([HA(aq.)][OH^(-)(aq.)])/([A^(-)(aq.)]) B^(+)(aq.)+H_(2)O(l)hArrBOH(aq.)+H^(+)(aq.) " " K_(h)=(K_(w))/(K_(b))rArr([BOH(aq.)][H^(+)(aq.)])/([B^(-)(aq.)]) Calculate percentage degreeof hydrolysis in a 0.1 M solution of CH_(3)COONa.(K_(a)"of"CH_(3)COOH=10^(-5))

Why is CH_(2)=CH-COOH a stronger acid than CH_(3)CH_(2)COOH ?

Phenol is a weaker acid than acetic acid because:

Hydrolysis of CH_(3)CH_(2)NO_(2) with 85% H_(2)SO_(4) gives :

The following equilibria is established when H_(2)SO_(4) is dissolved in acetic acid: H_(2)SO_(4) + CH_(3)COOH hArr Hoverset(Theta)SO_(4) + CH_(3)COOoverset(o+)H_(2) The set that characterised the conjugate acid-base pairs is:

Assertion (A): H_(2)SO_(4) acts as a base in the presence of HCIO_(4) . Reason (R) : Perchloride acid is stronger acid than H_(2)SO_(4) .

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VMC MODULES ENGLISH-IONIC EQUILIBRIUM-LEVEL 1
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  2. The ionisation of acetic acid in H(2)SO(4) compared to in water, is :

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  3. CH(3)COOH is weaker acid than H(2)SO(4). It is due to

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  4. Which of the following base is weakest ?

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