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Assuming H(2)SO(4) to be completely ioni...

Assuming `H_(2)SO_(4)` to be completely ionised the `pH` of a `0.05M` aqueous of sulphuric acid is approximately

A

0.005

B

2

C

1

D

0.01

Text Solution

Verified by Experts

The correct Answer is:
B
`pH=-log[H^(+)]=-log(0.005xx2)=2`
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