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What will be the resultant pH when 200mL...

What will be the resultant `pH` when `200mL` of an aqueous solution of `HCI (pH = 2.0)` is mixed with `300mL` of an aqueous solution of `NaOH (pH = 12.0)`?

A

10

B

2.7

C

4

D

11.3

Text Solution

Verified by Experts

The correct Answer is:
D
Milli moles of `[H^(+)]` = 2, Milli moles of `[OH^(-)] =3`
`pH=14 log [OH^(-)]=14 + "log" 1/500 = 14 –log 500=11.3`
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