If `K_(SP)` of `Ag_(2)S` is `10^(-17)`, the solubility of `Ag_(2) S` in 0.1 M solution of `Na_(2)S` will be :

Options

A. `10^(-8)`
B. `5xx10^(-9)`
C. `10^(-15)`
D. `10^(16)`

Answer

B

Explanation

`Ag_(2)S_((s)) to 2Ag_((aq))^(+) + S_((aq))^(2-)`
`K_(sp)=[Ag^(2+)][S^(2-)]` (`S^(2-)` will come predominantly from `Na_(2)S=0.1M`)
`10^(-17)=[Ag^(+2)]xx10^(-1) implies [Ag^(+)]=10^(-8)=2s implies s=5xx10^(-9)`