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one litre of H(2)O contains 10^(-7) mole...

one litre of `H_(2)O` contains `10^(-7)` moles `[H^(+)]`. Degrees of ionization of water is

A

`1.8xx10^(-7)%`

B

`0.8xx10^(-9)%`

C

`3.6xx10^(-9)%`

D

`3.6xx10^(-7)%`

Text Solution

Verified by Experts

The correct Answer is:
A
No. of Moles in 1L water =`1000/18`
Degree of ionization=`10^(-7)/(1000//18) xx100= 1.8xx10^(-7)%`
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