In the equation `I_(2)+I^(-) rarr, I_(3)^(-)` which is Lewis base

Options

A. `I_(2)`
B. `I_(2)`
C. `I_(3)^(-)`
D. None of these

Explanation

To determine which species is the Lewis base in the reaction \( I_2 + I^- \rightarrow I_3^- \), we can follow these steps:

### Step 1: Understand the Definition of Lewis Acid and Base
A Lewis base is defined as a species that can donate a pair of electrons, while a Lewis acid is a species that can accept a pair of electrons.

**Hint:** Remember that Lewis bases are electron pair donors.

### Step 2: Identify the Reactants
In the given reaction, we have two reactants: \( I_2 \) (iodine molecule) and \( I^- \) (iodide ion).

**Hint:** Look at the structure of each reactant to determine their roles in the reaction.

### Step 3: Analyze the Reaction
In the reaction, \( I^- \) donates a pair of electrons to \( I_2 \). This results in the formation of \( I_3^- \). Here, \( I_2 \) acts as an electron acceptor.

**Hint:** Identify which species is donating electrons and which is accepting them.

### Step 4: Identify the Lewis Base
Since \( I^- \) donates a pair of electrons to \( I_2 \), \( I^- \) is the Lewis base in this reaction.

**Hint:** The species that donates electrons is always the Lewis base.

### Conclusion
Thus, in the reaction \( I_2 + I^- \rightarrow I_3^- \), the Lewis base is \( I^- \).

### Final Answer
The Lewis base in the equation is \( I^- \).

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