Home
Class 12
MATHS
The equation of a curve passing through ...

The equation of a curve passing through origin is given by `y = int x^(3) cos x^(4) dx ` . If the equation of the curve is wirtten in the form x = g(y) , then

A

`g(y) root(3)(sin^(-1) (4y))`

B

`g(y) = sqrt(sin^(-1)(4y))`

C

`g(y) = root(4)(sin^(-1)(4y))`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • INTEGRAL CALCULUS-1

    VMC MODULES ENGLISH|Exercise LEVEL 2|50 Videos

  • INTEGRAL CALCULUS-1

    VMC MODULES ENGLISH|Exercise Numerical value Type of JEE Main|15 Videos

  • INTEGRAL CALCULUS-1

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (ARCHIVE)|25 Videos

  • INTEGRAL CALCULUS - 2

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|103 Videos

  • INVERSE TRIGONOMETRY

    VMC MODULES ENGLISH|Exercise JEE ADVANCED ( ARCHIVE )|10 Videos

Similar Questions

Explore conceptually related problems

Let the equation of a curve passing through the point (0,1) be given b y=intx^2e^(x^3)dx . If the equation of the curve is written in the form x=f(y) , then f(y) is

The slope of the tangent at (x , y) to a curve passing through (1,pi/4) is given by y/x-cos^2(y/x), then the equation of the curve is

The equation of a curve passing through (2,7/2) and having gradient 1-1/(x^2) at (x , y) is

If equation of the curve is y^2=4x then find the slope of normal to the curve

The equation of the curve passing through (3, 9) which satisfies dy //dx =x +1//x^2 is :

A curve passes through the point (0,1) and the gradient at (x,y) on it is y(xy-1) . The equation of the curve is

Find the equation of a curve passing through the origin given that the slope of the tangent to the curve at any point (x, y) is equal to the sum of the coordinates of the point.

Find the equation of a curve passing through the origin given that the slope of the tangent to the curve at any point (x, y) is equal to the sum of the coordinates of the point.

The slope of the tangent at (x , y) to a curve passing through a point (2,1) is (x^2+y^2)/(2x y) , then the equation of the curve is

The slope of the tangent at (x , y) to a curve passing through a point (2,1) is (x^2+y^2)/(2x y) , then the equation of the curve is