Home
Class 12
CHEMISTRY
Following reaction takes place in one st...

Following reaction takes place in one step: `2NO +O_(2) + 2NO_(2)` How will the rate of above reaction change if the volume of reaction vessel is reduced to 1/3 rd of original volume? Will there be any change in the order of reaction?

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the reaction and how the change in volume affects the rate of the reaction. ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction given is: \[ 2 \text{NO} + \text{O}_2 \rightarrow 2 \text{NO}_2 \] ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    VMC MODULES ENGLISH|Exercise Level-0 (Long Answer Type )|6 Videos

  • CHEMICAL KINETICS

    VMC MODULES ENGLISH|Exercise Level-1|75 Videos

  • CHEMICAL KINETICS

    VMC MODULES ENGLISH|Exercise Level-0 ( Short Answer Type-I )|8 Videos

  • CHEMICAL EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE - G|10 Videos

  • CHEMICAL THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise IN - CHAPTER EXERCISE - L|10 Videos

Similar Questions

Explore conceptually related problems

For an elementary reaction. A + 2B rightarrow C if volume of the vessel is reduced to 1/3 of its original volume the rate of the reaction will

How will the rate of reaction 2SO_(2)(g) + O_(2)(g) rarr 2SO_(3)(g) change if the volume of the reaction vessel is halved?

Show by uisng rate laws how much the rate of reaction 2NO(g) + O_(2)(g) rarr 2NO(g) will change if the volume of the reaction vessel is diminished to 1//3 of its initial volume.

For an elementary reaction 2A+B rarr A_(2)B if the volume of vessel is quickly reduced to half of it's original volume then rate of reaction will :

The reaction, 2NO(g)+O_(2)(g)hArr2NO_(2)(g), is of first order. If the volume of reaction vessel is reduced to (1)/(3) , the rate of reaction would be

Write the rate equation for the reaction 2A + B to C if the order of the reaction is zero .

Equal volumes of H_(2) and Cl_(2) are mixed. How will the volume of the mixtuer change after the reaction?

The rate of a gaseous reaction is given by the expression k[A][B] . If The volume of reaction vessel is suddenly reduced to one-fourth of the initial volume, the reaction rate relative to the original rate will be :

The rate of a gaseous reaction is given by the expression k[A][B] . If The volume of reaction vessel is suddenly reduced to one-fourth of the initial volume, the reaction rate relative to the original rate will be :

A reaction is second order with respect to a reaction. How is the rate of reaction affected if the (a) doubled, (b) reduced to 1//2 ?