Home
Class 12
CHEMISTRY
A first order reaction takes 69.3 min fo...

A first order reaction takes 69.3 min for 50% completion. What is the time in min for 80% completion?

Text Solution

Verified by Experts

`t_(1//2)=69.3n` ub
`k =(0.693)/(69.3)=0.01" m in"^(-1)`
`t_(80%)=(2.303)/(k)log""([R_(0)])/([R])`
`=(2.303)/(0.01)log""(R_(0))/((20)/(100)R_(0))=(2.303)/(0.01) xx log 5`
`=(2.303)/(0.01)xx0.6990=160.97` m in =2.68 hrs.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    VMC MODULES ENGLISH|Exercise Level-0 (Long Answer Type )|6 Videos

  • CHEMICAL KINETICS

    VMC MODULES ENGLISH|Exercise Level-1|75 Videos

  • CHEMICAL KINETICS

    VMC MODULES ENGLISH|Exercise Level-0 ( Short Answer Type-I )|8 Videos

  • CHEMICAL EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE - G|10 Videos

  • CHEMICAL THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise IN - CHAPTER EXERCISE - L|10 Videos

Similar Questions

Explore conceptually related problems

(a) For a reaction A+BrarrP, the rate is given by Rate =K[A][B]^(2) (i) How is the rate of reaction affected if the concentration of B is doubled ? (ii) What is the overall order of reaction if A is present in large excess ? (b) A first order reaction takes 30 minutes for 50% completion. Calculate the time required for 90% completion of this reaction.

A first order reaction takes 69.3 minutes for 50% completion. How much time will be needed for 80% completion?

A first order reaction is 20% complete in 10 min. What is the rate constant?

A zero-order reaction is 25% complete in 30seconds. What time does it take for 50% completion?

A first order reaction is 50% complete in 20 minutes. What is its rate constant ?

90% of a first order reaction was completed in 100 min . How much time it will take for 80% completion of a reaction

In the case of a first order reaction, the ratio of time required for 99.9% completion to 50% completion is