The raction `2FeCl_(3) + SnCl_(2) rarr 2FeCl_(2) + SnCl_(4)` is an example of

Options

A. first order reaction
B. second order reaction
C. third order reaction
D. None of these

Explanation

To determine the order of the reaction given by the equation:

\[ 2FeCl_3 + SnCl_2 \rightarrow 2FeCl_2 + SnCl_4 \]

we will follow these steps:

### Step 1: Identify the reactants and their coefficients
In the reaction, we have:
- \( FeCl_3 \) with a coefficient of 2
- \( SnCl_2 \) with a coefficient of 1

### Step 2: Write the general form of the rate law
The rate law for a general reaction can be expressed as:
\[ R = k [A]^a [B]^b \]
where:
- \( R \) is the rate of the reaction,
- \( k \) is the rate constant,
- \( [A] \) and \( [B] \) are the concentrations of the reactants,
- \( a \) and \( b \) are the coefficients of the reactants in the balanced equation.

### Step 3: Apply the coefficients to the rate law
For our specific reaction:
- The concentration of \( FeCl_3 \) is raised to the power of its coefficient (2).
- The concentration of \( SnCl_2 \) is raised to the power of its coefficient (1).

Thus, the rate law can be written as:
\[ R = k [FeCl_3]^2 [SnCl_2]^1 \]

### Step 4: Determine the order of the reaction
The order of the reaction is the sum of the powers of the concentrations of the reactants in the rate law. Therefore:
- The order contributed by \( FeCl_3 \) is 2.
- The order contributed by \( SnCl_2 \) is 1.

Adding these together gives:
\[ \text{Order of reaction} = 2 + 1 = 3 \]

### Conclusion
The order of the reaction is 3, which means it is a third-order reaction.

### Final Answer
The reaction \( 2FeCl_3 + SnCl_2 \rightarrow 2FeCl_2 + SnCl_4 \) is an example of a **third-order reaction**.

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