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In a first order reaction, the concentra...

In a first order reaction, the concentration of the reactant decreases form `800 "mol dm"^(-3)` to `50 "mol dm"^(-3)` in `2 xx 10^(4) s`. The rate constant of the reaction (in `s^(-1)`) is

A

`2xx10^(4)`

B

`3.45xx10^(-5)`

C

`1.386xx10^(-4)`

D

`2xx10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
C
`k=(1)/(2xx10^(4))ln ((800)/(50))=(1)/(2xx10^(4))ln 16=(4xx0.693)/(2xx10^(4))`
`k=1.386xx10^(-4)" sec"^(-1)`
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