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The rate of reaction between two reacta...

The rate of reaction between two reactants `A` and `B` decreases by factor `4` if the concentration of reactant `B` is doubled. The order of this reaction with respect to `B` is

A

2

B

`-1`

C

1

D

`-2`

Text Solution

Verified by Experts

The correct Answer is:
D
`r=k [A]^(n) [B]^(n)`
`r'=(r )/(4)=k[A]^(n) (2[B])^(n)" "rArr (r )/(r')=4=((1)/(2))^(n) rArr n=-2`
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